The roots of the equation x² + 3x - 10 are: a. 2,-5 b. -2,5 c. 2,5 d. -2, -5
Question
The roots of the equation x² + 3x - 10 are: a. 2,-5 b. -2,5 c. 2,5 d. -2, -5
Solution
The roots of a quadratic equation can be found using the quadratic formula, which is:
x = [-b ± sqrt(b² - 4ac)] / 2a
In this case, the equation is x² + 3x - 10 = 0, so a = 1, b = 3, and c = -10.
Substituting these values into the quadratic formula gives:
x = [-3 ± sqrt((3)² - 41(-10))] / 2*1 x = [-3 ± sqrt(9 + 40)] / 2 x = [-3 ± sqrt(49)] / 2 x = [-3 ± 7] / 2
This gives the two solutions x = 2 and x = -5. Therefore, the correct answer is a. 2,-5.
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