What are the elements present in the array of the following C code?int array[5] = {5};a.5, 5, 5, 5, 5b.5, 0, 0, 0, 0c.5, (garbage), (garbage), (garbage), (garbage)d.(garbage), (garbage), (garbage), (garbage), 5
Question
What are the elements present in the array of the following C code?int array[5] = {5};a.5, 5, 5, 5, 5b.5, 0, 0, 0, 0c.5, (garbage), (garbage), (garbage), (garbage)d.(garbage), (garbage), (garbage), (garbage), 5
Solution 1
The given C code declares an array named "array" of size 5 and initializes the first element with the value 5. The remaining elements of the array will be automatically initialized to 0. Therefore, the elements present in the array are:
b. 5, 0, 0, 0, 0
Solution 2
The elements present in the array of the given C code are:
b. 5, 0, 0, 0, 0
Explanation:
In C, when you declare an array and initialize it with a single value, the first element of the array gets that value and the rest of the elements are automatically initialized to 0. So, in this case, the first element of the array is 5 and the rest of the elements (from index 1 to 4) are 0.
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