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What will be the output of the following C code?void main() {  int a[] = {1,2,3,4,5}, *p;  p = a;  ++*p;  printf("%d ", *p);p += 2;  printf("%d ", *p);}a.24b.22c.23d.34

Question

What will be the output of the following C code?void main() {  int a[] = {1,2,3,4,5}, *p;  p = a;  ++*p;  printf("%d ", *p);p += 2;  printf("%d ", *p);}a.24b.22c.23d.34

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Solution 1

To determine the output of the given code, let's analyze it step by step:

  1. Declare an integer array a with values {1, 2, 3, 4, 5}.
  2. Declare a pointer variable p.
  3. Assign the address of the first element of array a to pointer p.
  4. Increment the value pointed by p by 1. This means the value at a[0] will become 2.
  5. Print the value pointed by p, which is 2.
  6. Increment the pointer p by 2 positions. This means p will now point to a[2].
  7. Print the value pointed by p, which is 3.

Therefore, the output of the given C code will be "2 3".

Answer: c. 23

This problem has been solved

Solution 2

To determine the output of the given code, let's analyze it step by step:

  1. Declare an integer array a with values {1, 2, 3, 4, 5}.
  2. Declare a pointer variable p.
  3. Assign the address of the first element of array a to pointer p.
  4. Increment the value pointed by p by 1. This means the value at a[0] will become 2.
  5. Print the value pointed by p, which is 2.
  6. Increment the pointer p by 2 positions. This means p will now point to a[2].
  7. Print the value pointed by p, which is 3.

Therefore, the output of the given C code will be "2 3".

Answer: c. 23

This problem has been solved

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