Which of the following represents the correct order of the acidity in the given compounds?1)FCH COOH CH COOH BrCH COOH ClCH COOH 2 3 2 2 2)BrCH COOH ClCH COOH FCH COOH CH COOH 2 2 2 3 3)FCH COOH ClCH COOH BrCH COOH CH COOH 2 2 2 3 4)CH COOH BrCH COOH ClCH COOH FCH COOH
Question
Which of the following represents the correct order of the acidity in the given compounds?1)FCH COOH CH COOH BrCH COOH ClCH COOH 2 3 2 2 2)BrCH COOH ClCH COOH FCH COOH CH COOH 2 2 2 3 3)FCH COOH ClCH COOH BrCH COOH CH COOH 2 2 2 3 4)CH COOH BrCH COOH ClCH COOH FCH COOH
Solution
The acidity of a compound is determined by the stability of its conjugate base. The more stable the conjugate base, the more acidic the compound.
The stability of the conjugate base is increased by electron-withdrawing groups, which can stabilize the negative charge on the conjugate base.
In the given compounds, the electron-withdrawing groups are the halogens (F, Cl, Br). The strength of these groups follows the order F > Cl > Br, with fluorine being the strongest electron-withdrawing group and bromine being the weakest.
Therefore, the correct order of acidity should be FCH2COOH > ClCH2COOH > BrCH2COOH > CH3COOH, which corresponds to option 1.
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