The diagram at the right shows six positions of a 0.49-kg ball bouncing across a 4.0-meter-high physics room. Information regarding the vertical position is shown. Assume that the floor is the reference level for zero potential energy. Determine the gravitational potential energy of the 0.49-kg ball at position A:
Question
The diagram at the right shows six positions of a 0.49-kg ball bouncing across a 4.0-meter-high physics room. Information regarding the vertical position is shown. Assume that the floor is the reference level for zero potential energy. Determine the gravitational potential energy of the 0.49-kg ball at position A:
Solution
To calculate the gravitational potential energy, we use the formula:
PE = mgh
where: PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height above the reference point.
Given: m = 0.49 kg (mass of the ball), g = 9.8 m/s² (acceleration due to gravity on Earth), and h = 4.0 m (height of the room, which is also the height of the ball at position A since it's mentioned that the ball is bouncing across a 4.0-meter-high room).
Substituting these values into the formula, we get:
PE = 0.49 kg * 9.8 m/s² * 4.0 m = 19.176 Joules
So, the gravitational potential energy of the 0.49-kg ball at position A is 19.176 Joules.
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