Ques 1: A rocket, rising vertically, is tracked by a radar station that is on the ground 5 mi from thelaunchpad. How fast is the rocket rising when it is 4 mi high and its distance from the radar station isincreasing at a rate of 2000 mi/h
Question
Ques 1: A rocket, rising vertically, is tracked by a radar station that is on the ground 5 mi from thelaunchpad. How fast is the rocket rising when it is 4 mi high and its distance from the radar station isincreasing at a rate of 2000 mi/h
Solution
To find the speed at which the rocket is rising, we can use the concept of related rates. Let's denote the height of the rocket as h and the distance between the rocket and the radar station as d.
Given:
- The distance between the radar station and the launchpad is 5 mi.
- The rate at which the distance between the rocket and the radar station is increasing is 2000 mi/h.
We need to find the rate at which the rocket is rising when it is 4 mi high.
Step 1: Set up the equation relating the variables. Using the Pythagorean theorem, we can relate the height of the rocket (h) and the distance between the rocket and the radar station (d): d^2 = h^2 + 5^2
Step 2: Differentiate both sides of the equation with respect to time (t). 2d * dd/dt = 2h * dh/dt
Step 3: Substitute the given values. When the rocket is 4 mi high, h = 4. Also, we are given that dd/dt = 2000 mi/h.
Step 4: Solve for dh/dt. Substituting the values into the equation from step 2: 2(5) * 2000 = 2(4) * dh/dt
Simplifying the equation: 10000 = 8 * dh/dt
Dividing both sides by 8: dh/dt = 10000/8
Simplifying further: dh/dt = 1250 mi/h
Therefore, the rocket is rising at a speed of 1250 mi/h when it is 4 mi high and the distance between the rocket and the radar station is increasing at a rate of 2000 mi/h.
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