Knowee
Questions
Features
Study Tools

of 5PDF ViewerW5 – Applications of Quadratics Unit 5MPM2DJensen1) A model rocket is launched from the deck in Jim’s backyard and the path followed by the rocket can bemodelled by the relation ℎ = −5% ! + 100% + 15, where ℎ, in meters, is the height that the model rocket reachesafter % seconds.a) What is the height of the deck?b) What is the height of the model rocket after 2 s?c) What is the maximum height reached by the model rocket?d) How long did the model rocket take to reach this height?e) How long was the model rocket above 200 m?f) How long the model rocket was in the air.2) A harbour ferry service has about 240 000 riders per day for a fare of $2. The port authority wants toincrease the fare to help with increasing operational costs. Research has shown that for every $0.10 increase inthe fare the number of riders will drop by 10 000.a) What increase in the fare will maximize the revenue?b) What is the new fare?c) What is the revenue that will be received from the new fare?3) A rectangular lawn measures 30 m by 40 m. Jason is cutting the lawn from the outside perimeter in towardthe center by cutting strips along the entire perimeter first, then continuing as he cuts toward the center. Howwide is the strip that has been cut along the outside when the area is half cut?

Question

of 5PDF ViewerW5 – Applications of Quadratics Unit 5MPM2DJensen1) A model rocket is launched from the deck in Jim’s backyard and the path followed by the rocket can bemodelled by the relation ℎ = −5% ! + 100% + 15, where ℎ, in meters, is the height that the model rocket reachesafter % seconds.a) What is the height of the deck?b) What is the height of the model rocket after 2 s?c) What is the maximum height reached by the model rocket?d) How long did the model rocket take to reach this height?e) How long was the model rocket above 200 m?f) How long the model rocket was in the air.2) A harbour ferry service has about 240 000 riders per day for a fare of 2.Theportauthoritywantstoincreasethefaretohelpwithincreasingoperationalcosts.Researchhasshownthatforevery2. The port authority wants toincrease the fare to help with increasing operational costs. Research has shown that for every 0.10 increase inthe fare the number of riders will drop by 10 000.a) What increase in the fare will maximize the revenue?b) What is the new fare?c) What is the revenue that will be received from the new fare?3) A rectangular lawn measures 30 m by 40 m. Jason is cutting the lawn from the outside perimeter in towardthe center by cutting strips along the entire perimeter first, then continuing as he cuts toward the center. Howwide is the strip that has been cut along the outside when the area is half cut?

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

The text you provided contains several mathematical problems. Let's solve them one by one:

  1. The equation given is h = -5t^2 + 100t + 15, where h is the height and t is the time in seconds.

a) The height of the deck is the value of h when t=0. Substituting t=0 in the equation, we get h = -5(0)^2 + 100(0) + 15 = 15 meters.

b) The height of the rocket after 2 seconds is found by substituting t=2 in the equation. h = -5(2)^2 + 100(2) + 15 = 175 meters.

c) The maximum height reached by the rocket is the vertex of the parabola represented by the equation. The t-coordinate of the vertex is given by -b/2a = -100/(-10) = 10 seconds. Substituting t=10 in the equation, we get h = -5(10)^2 + 100(10) + 15 = 515 meters.

d) The rocket took 10 seconds to reach the maximum height.

e) To find out how long the rocket was above 200 meters, we need to solve the equation -5t^2 + 100t + 15 = 200. Solving this quadratic equation, we get t = 5 seconds and t = 15 seconds. So, the rocket was above 200 meters for 15 - 5 = 10 seconds.

f) The rocket was in the air until it hit the ground, i.e., when h=0. Solving the equation -5t^2 + 100t + 15 = 0, we get t = 15 seconds.

  1. Let x be the increase in fare. The number of riders will be 240000 - 10000x and the fare will be 2 + 0.10x. The revenue is the product of the number of riders and the fare.

a) To maximize the revenue, we

This problem has been solved

Similar Questions

A model rocket is launched from the deck in Jim’s backyard and the path followed by the rocket can bemodelled by the relation ℎ = −5% ! + 100% + 15, where ℎ, in meters, is the height that the model rocket reachesafter % seconds.a) What is the height of the deck?

ProblemEarlier, you were told about a toy rocket fired into the air from the top of a barn. Its height (hℎ) above the ground in yards after x𝑥 seconds is given by the function:h(x)=−5x2+10x+20ℎ(𝑥)=−5𝑥2+10𝑥+20What was the maximum height of the rocket? SolutionThe maximum height was reached by the rocket at one second as you found in part b from the previous example. It takes second to reach the maximum height. We will substitute that value in for x𝑥 in our function and simplify.The maximum height reached by the rocket was yards. What is the time it takes for the rocket to hit the ground? (Use a graph or any other method to solve.)It takes approximately seconds for the rocket to hit the ground. (Round to the nearest tenth.)CheckQuestion 9

Ques 1: A rocket, rising vertically, is tracked by a radar station that is on the ground 5 mi from thelaunchpad. How fast is the rocket rising when it is 4 mi high and its distance from the radar station isincreasing at a rate of 2000 mi/h

(a)The function 𝑓(𝑡)=−5𝑡2+20𝑡+60f\left(t\right)=-5t^2+20t+60f(t)=−5t 2 +20t+60 models the approximate height of an object 𝑡tt seconds after it is launched. How many seconds does it take the object to hit the ground? (Enter only the number)

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.y, equals, minus, 16, x, squared, plus, 162, x, plus, 82y=−16x 2 +162x+82AnswerAttempt 1 out of 2

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.