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When a coin is tossed four times, sixteen equally likely outcomes are possible as shown below: HHHHHHHTHHTHHHTTHTHHHTHTHTTHHTTTTHHHTHHTTHTHTHTTTTHHTTHTTTTHTTTT Let X denote the total number of tails obtained in the four tosses.  Create a probability distribution of the random variable X.  xP(X)

Question

When a coin is tossed four times, sixteen equally likely outcomes are possible as shown below: HHHHHHHTHHTHHHTTHTHHHTHTHTTHHTTTTHHHTHHTTHTHTHTTTTHHTTHTTTTHTTTT Let X denote the total number of tails obtained in the four tosses.  Create a probability distribution of the random variable X.  xP(X)

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Solution

The random variable X can take on the values 0, 1, 2, 3, 4. These values represent the number of tails that can be obtained when a coin is tossed four times.

To create a probability distribution of the random variable X, we need to find the probability of each value of X.

  1. X = 0 (No tails, all heads): There is only 1 outcome (HHHH) out of 16 that has no tails. So, P(X=0) = 1/16.

  2. X = 1 (One tail): There are 4 outcomes (HHHT, HHTH, HTHH, THHH) out of 16 that have one tail. So, P(X=1) = 4/16 = 1/4.

  3. X = 2 (Two tails): There are 6 outcomes (HHTT, HTHT, HTTH, THHT, THTH, TTHH) out of 16 that have two tails. So, P(X=2) = 6/16 = 3/8.

  4. X = 3 (Three tails): There are 4 outcomes (THHT, THTH, TTHH, HTTT) out of 16 that have three tails. So, P(X=3) = 4/16 = 1/4.

  5. X = 4 (Four tails): There is only 1 outcome (TTTT) out of 16 that has four tails. So, P(X=4) = 1/16.

So, the probability distribution of the random variable X is:

X P(X)
0 1/16
1 1/4
2 3/8
3 1/4
4 1/16

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