Four unbiased coins are tossed simultaneously. The expected number of heads is :X: 0 1 2 3 4P(x) 1/16 4/16 6/16 4/16 1/16(a) 1(b) 2(c) 3(d) 4
Question
Four unbiased coins are tossed simultaneously. The expected number of heads is :X: 0 1 2 3 4P(x) 1/16 4/16 6/16 4/16 1/16(a) 1(b) 2(c) 3(d) 4
Solution
To find the expected number of heads when four unbiased coins are tossed simultaneously, we need to multiply each possible outcome by its corresponding probability and sum them up.
Let's calculate the expected number of heads step by step:
Step 1: Multiply the number of heads (X) by its probability (P(x)) for each possible outcome: 0 * 1/16 = 0 1 * 4/16 = 1/4 2 * 6/16 = 3/4 3 * 4/16 = 1/4 4 * 1/16 = 1/4
Step 2: Sum up the results from step 1: 0 + 1/4 + 3/4 + 1/4 + 1/4 = 2
Therefore, the expected number of heads is 2.
So, the answer to the question is (b) 2.
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