In a gel electrophoresis experiment, the movement of peptides is determined by their net charge. At a given pH, a peptide will have a net positive charge if the pH is above its isoelectric point (pI), and a net negative charge if the pH is below its pI.

The isoelectric point (pI) is the pH at which a particular molecule or surface carries no net electrical charge.

The pI values of the amino acids are as follows:

Tyr (Y) - 5.66
Trp (W) - 5.89
Asp (D) - 2.77
Leu (L) - 5.98
Lys (K) - 9.74
Gly (G) - 5.97
Cys (C) - 5.07
Asn (N) - 5.41
Arg (R) - 10.76
His (H) - 7.59
Glu (E) - 3.22
Gln (Q) - 5.65
Ile (I) - 6.02

At pH 5, the peptides with Asp (D) and Glu (E) would have a net negative charge because their pI values are below 5. Therefore, they would move towards the positive terminal.

The peptides with Lys (K), Arg (R), and His (H) would have a net positive charge because their pI values are above 5. Therefore, they would move towards the negative terminal.

So, the peptide that would move towards the negative terminal in a gel electrophoresis experiment run at pH 5 is B. Asp–Lys–Gly–Cys.

Question

In a gel electrophoresis experiment, the movement of peptides is determined by their net charge. At a given pH, a peptide will have a net positive charge if the pH is above its isoelectric point (pI), and a net negative charge if the pH is below its pI.

The isoelectric point (pI) is the pH at which a particular molecule or surface carries no net electrical charge.

The pI values of the amino acids are as follows:

Tyr (Y) - 5.66
Trp (W) - 5.89
Asp (D) - 2.77
Leu (L) - 5.98
Lys (K) - 9.74
Gly (G) - 5.97
Cys (C) - 5.07
Asn (N) - 5.41
Arg (R) - 10.76
His (H) - 7.59
Glu (E) - 3.22
Gln (Q) - 5.65
Ile (I) - 6.02

At pH 5, the peptides with Asp (D) and Glu (E) would have a net negative charge because their pI values are below 5. Therefore, they would move towards the positive terminal.

The peptides with Lys (K), Arg (R), and His (H) would have a net positive charge because their pI values are above 5. Therefore, they would move towards the negative terminal.

So, the peptide that would move towards the negative terminal in a gel electrophoresis experiment run at pH 5 is B. Asp–Lys–Gly–Cys.

Knowee AI · Accepted Answer

In a gel electrophoresis experiment, the movement of peptides is determined by their net charge. At a given pH, a peptide will have a net positive charge if the pH is above its isoelectric point (pI), and a net negative charge if the pH is below its pI.

The isoelectric point (pI) is the pH at which a particular molecule or surface carries no net electrical charge.

The pI values of the amino acids are as follows:

Tyr (Y) - 5.66
Trp (W) - 5.89
Asp (D) - 2.77
Leu (L) - 5.98
Lys (K) - 9.74
Gly (G) - 5.97
Cys (C) - 5.07
Asn (N) - 5.41
Arg (R) - 10.76
His (H) - 7.59
Glu (E) - 3.22
Gln (Q) - 5.65
Ile (I) - 6.02

At pH 5, the peptides with Asp (D) and Glu (E) would have a net negative charge because their pI values are below 5. Therefore, they would move towards the positive terminal.

The peptides with Lys (K), Arg (R), and His (H) would have a net positive charge because their pI values are above 5. Therefore, they would move towards the negative terminal.

So, the peptide that would move towards the negative terminal in a gel electrophoresis experiment run at pH 5 is B. Asp–Lys–Gly–Cys.

Which of the following peptides would move towards the negative terminal in a gel electrophoresis experiment run at pH 5?Question 13 Answer Choices A. Tyr–Trp–Asp–Leu B. Asp–Lys–Gly–Cys C. Asn–Arg–His–Glu D. Glu–Gln–Lys–Ile

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