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The content of an 8-bit register is 01011010. The register is shifted ten times to the rightwith the serial input being 1100111010 (i.e. 1 is shifted in first etc.). What is the content ofthe register after each shift?

Question

The content of an 8-bit register is 01011010. The register is shifted ten times to the rightwith the serial input being 1100111010 (i.e. 1 is shifted in first etc.). What is the content ofthe register after each shift?

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Solution

Sure, here is the step by step process:

  1. Initial content of the register: 01011010
  2. After 1st shift (1 enters): 10101101
  3. After 2nd shift (1 enters): 11010110
  4. After 3rd shift (0 enters): 01101011
  5. After 4th shift (0 enters): 00110101
  6. After 5th shift (1 enters): 10011010
  7. After 6th shift (1 enters): 11001101
  8. After 7th shift (7 enters): 11100110
  9. After 8th shift (0 enters): 01110011
  10. After 9th shift (1 enters): 10111001
  11. After 10th shift (0 enters): 01011100

So, after ten shifts, the content of the register is 01011100.

This problem has been solved

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