Assume that a 4-bit serial in-serial out (SISO) shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)a.1100b.0000c.0011d.1111
Question
Assume that a 4-bit serial in-serial out (SISO) shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)a.1100b.0000c.0011d.1111
Solution
The 4-bit pattern after the second clock pulse will be 0011.
Here's the step-by-step process:
- Initially, the shift register is clear, so it's 0000.
- After the first clock pulse, the right-most bit (0) is shifted out and the first bit of the nibble (1) is shifted in, resulting in 1000.
- After the second clock pulse, the right-most bit (0) is shifted out and the second bit of the nibble (1) is shifted in, resulting in 1100.
So, the correct answer is c. 0011.
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