96 g of B2O3 is dissolved in water to produce a solution with a concentration of 1.86 M. What is the volume of this solution in liters?
Question
96 g of B2O3 is dissolved in water to produce a solution with a concentration of 1.86 M. What is the volume of this solution in liters?
Solution
To solve this problem, we need to use the formula for molarity which is M = moles/L.
Step 1: Calculate the molar mass of B2O3. The molar mass of Boron (B) is about 10.81 g/mol and the molar mass of Oxygen (O) is about 16.00 g/mol. So, the molar mass of B2O3 = 2(10.81 g/mol) + 3(16.00 g/mol) = 69.62 g/mol.
Step 2: Calculate the number of moles of B2O3. We know that moles = mass/molar mass. So, moles of B2O3 = 96 g / 69.62 g/mol = 1.38 moles.
Step 3: Use the molarity formula to find the volume. We know that M = moles/L. So, L = moles/M = 1.38 moles / 1.86 M = 0.74 L.
So, the volume of the solution is 0.74 liters.
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