A piece of paper with mass 0.002 kg falls from a height of 8 m. Under realistic conditions, it experiences air resistance. Based on what you know about friction, what can you say about the kinetic energy of the paper as it reaches the ground? Acceleration due to gravity is g = 9.8 m/s2.A.KE > 0.16 JB.KE < 0.16 JC.KE = 0.16 JD.KE = 0 J
Question
A piece of paper with mass 0.002 kg falls from a height of 8 m. Under realistic conditions, it experiences air resistance. Based on what you know about friction, what can you say about the kinetic energy of the paper as it reaches the ground? Acceleration due to gravity is g = 9.8 m/s2.A.KE > 0.16 JB.KE < 0.16 JC.KE = 0.16 JD.KE = 0 J
Solution
First, let's calculate the potential energy of the paper at the height of 8m. The formula for potential energy is PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.
PE = 0.002 kg * 9.8 m/s^2 * 8 m = 0.16 J
In an ideal situation (without air resistance), this potential energy would be completely converted into kinetic energy (KE) as the paper falls. So, the kinetic energy of the paper when it reaches the ground would also be 0.16 J.
However, the question states that the paper experiences air resistance. Air resistance is a form of friction, which is a non-conservative force. This means that it takes away some of the energy of the system. In this case, it will reduce the kinetic energy of the paper as it falls.
Therefore, the kinetic energy of the paper when it reaches the ground will be less than the initial potential energy. So, the correct answer is:
B. KE < 0.16 J
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