A boy of mass 17 kg is playing on a reversible see saw with his mother of mass 55 kg.If the boy goes down by 6 metres  ,what height will his mother go up by?  (write upto two decimal places)6.87 m9.88 m1.85 m4.33 m

The problem can be solved using the principle of conservation of energy. In a reversible seesaw, the potential energy of the boy when he is up is equal to the potential energy of his mother when she is up.

The potential energy (PE) is given by the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and h is the height.

Let's denote: m1 = mass of the boy = 17 kg h1 = height the boy goes down = 6 m m2 = mass of the mother = 55 kg h2 = height the mother goes up (this is what we want to find)

From the conservation of energy, we have m1gh1 = m2gh2. We can cancel out g from both sides, so we get m1h1 = m2h2.

Substituting the known values, we get 176 = 55h2. Solving for h2, we get h2 = (17*6) / 55 = 1.85 m.

So, the mother will go up by approximately 1.85 meters.