Determine the limiting reactant when 12.00 g of carbon reacts with 12.00 g of oxygen according to the following equation: C(s) + O2(g) → CO2(g)not enough informationO2CO2C
Question
Determine the limiting reactant when 12.00 g of carbon reacts with 12.00 g of oxygen according to the following equation: C(s) + O2(g) → CO2(g)not enough informationO2CO2C
Solution
To determine the limiting reactant, we first need to calculate the number of moles of each reactant.
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The molar mass of carbon (C) is approximately 12.01 g/mol and the molar mass of oxygen (O2) is approximately 32.00 g/mol.
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Calculate the number of moles for each reactant:
- For carbon: 12.00 g / 12.01 g/mol = 0.999 moles
- For oxygen: 12.00 g / 32.00 g/mol = 0.375 moles
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The balanced chemical equation tells us that one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.
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Comparing the number of moles of each reactant, we can see that we have more moles of carbon than we do of oxygen.
Therefore, oxygen (O2) is the limiting reactant because it will be completely used up before all the carbon is reacted.
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