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Account for the ability of phosphorus to form five bonds, as in PF5

Question

Account for the ability of phosphorus to form five bonds, as in PF5

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Solution

Phosphorus (P) is in the 15th group (or VA group) of the periodic table, which means it has five valence electrons. These are the electrons that are involved in forming chemical bonds with other atoms.

In its ground state, the electronic configuration of phosphorus is 1s2 2s2 2p6 3s2 3p3. The 3s and 3p orbitals are the outermost and are half-filled.

However, phosphorus also has empty 3d orbitals that can be used in bonding. When phosphorus forms bonds, it can undergo 'hybridization' - a process where atomic orbitals mix to form new, identical hybrid orbitals.

In the case of PF5, phosphorus undergoes sp3d hybridization. This means that one 3s, three 3p and one 3d orbitals mix to form five sp3d hybrid orbitals.

Each of these hybrid orbitals can form a bond with an atom of Fluorine (F), which has seven valence electrons and needs one more to complete its octet.

So, the ability of phosphorus to form five bonds, as in PF5, is due to the availability of empty 3d orbitals and the process of hybridization.

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