To solve this problem, we can use Bernoulli's equation, which in this case simplifies to the Torricelli's theorem, as the tank is open to the atmosphere and we can neglect friction and minor losses.

Torricelli's theorem states that the speed v of efflux of a fluid under the force of gravity from a tank is given by v = sqrt(2gh), where g is the acceleration due to gravity and h is the height of the fluid above the point of efflux.

Given:
v = 6.6 m/s
g = 9.81 m/s^2

We need to find h.

Rearranging Torricelli's theorem to solve for h gives us:

h = v^2 / 2g

Substituting the given values into the equation:

h = (6.6 m/s)^2 / (2 * 9.81 m/s^2)

h = 43.56 m^2/s^2 / 19.62 m/s^2

h = 2.22 m

Therefore, the minimum height of the water in the tank is 2.22 m.

Question

To solve this problem, we can use Bernoulli's equation, which in this case simplifies to the Torricelli's theorem, as the tank is open to the atmosphere and we can neglect friction and minor losses.

Torricelli's theorem states that the speed v of efflux of a fluid under the force of gravity from a tank is given by v = sqrt(2gh), where g is the acceleration due to gravity and h is the height of the fluid above the point of efflux.

Given:
v = 6.6 m/s
g = 9.81 m/s^2

We need to find h.

Rearranging Torricelli's theorem to solve for h gives us:

h = v^2 / 2g

Substituting the given values into the equation:

h = (6.6 m/s)^2 / (2 * 9.81 m/s^2)

h = 43.56 m^2/s^2 / 19.62 m/s^2

h = 2.22 m

Therefore, the minimum height of the water in the tank is 2.22 m.

Knowee AI · Accepted Answer

To solve this problem, we can use Bernoulli's equation, which in this case simplifies to the Torricelli's theorem, as the tank is open to the atmosphere and we can neglect friction and minor losses.

Torricelli's theorem states that the speed v of efflux of a fluid under the force of gravity from a tank is given by v = sqrt(2gh), where g is the acceleration due to gravity and h is the height of the fluid above the point of efflux.

Given:
v = 6.6 m/s
g = 9.81 m/s^2

We need to find h.

Rearranging Torricelli's theorem to solve for h gives us:

h = v^2 / 2g

Substituting the given values into the equation:

h = (6.6 m/s)^2 / (2 * 9.81 m/s^2)

h = 43.56 m^2/s^2 / 19.62 m/s^2

h = 2.22 m

Therefore, the minimum height of the water in the tank is 2.22 m.

Water is withdrawn at the bottom of a large tank open to the atmosphere. The water velocity is 6.6 m/s. What is the minimum height of the water in the tank? You can neglect friction and minor losse Express your answer in m.

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