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In the following equations, t𝑡 is time in s, v𝑣 is velocity in m/s, and a𝑎 is acceleration in m/s2. Which of these equations is consistent with the units?Enter correct letter: a. v=at𝑣=𝑎𝑡b. v=a2t𝑣=𝑎2𝑡c. v=at2𝑣=𝑎𝑡2d. v=a2t

Question

In the following equations, t𝑡 is time in s, v𝑣 is velocity in m/s, and a𝑎 is acceleration in m/s2. Which of these equations is consistent with the units?Enter correct letter: a. v=at𝑣=𝑎𝑡b. v=a2t𝑣=𝑎2𝑡c. v=at2𝑣=𝑎𝑡2d. v=a2t

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Solution

The correct equation consistent with the units is a. v=at.

Here's why:

In the equation v=at, 'a' is acceleration which has the unit m/s² and 't' is time which has the unit s. When you multiply acceleration (m/s²) and time (s), the second in the denominator of acceleration's unit cancels out with the second in time's unit, leaving you with m/s, which is the unit for velocity.

So, the units are consistent in this equation.

The other equations (b, c, d) are not consistent with the units. For example, in equation b. v=a²t, when you square acceleration (a²), you get m²/s⁴ which, when multiplied by time (s), gives m²/s³, not m/s which is the unit for velocity. Similarly, you can check for the other equations.

This problem has been solved

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