Which of the following is the correct unit for acceleration?Metres squared per second squaredMetres per second squaredMetres squared per secondMetres per second2A lorry accelerates uniformly from rest to 20 m/s in 10 seconds. Calculate its acceleration.10 m/s22 m/s20.5 m/s2200 m/s23A car accelerates uniformly from 15 to 40 m/s in 5 seconds. Calculate its acceleration.8 m/s275 m/s23 m/s25 m/s24A home-made rocket accelerates uniformly from rest at a rate of 500 m/s2 for 0.1 seconds. Calculate its launch velocity.500 m/s0.0002 m/s50 m/s5000 m/s5A racing car accelerates uniformly from rest to 40 m/s over a distance of 400 m. Calculate its acceleration.0.05 m/s20.2 m/s22 m/s28 m/s26A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s2. Calculate the distance which it covers during this time.2 m46.9 m120 m30 m
Question
Which of the following is the correct unit for acceleration?Metres squared per second squaredMetres per second squaredMetres squared per secondMetres per second2A lorry accelerates uniformly from rest to 20 m/s in 10 seconds. Calculate its acceleration.10 m/s22 m/s20.5 m/s2200 m/s23A car accelerates uniformly from 15 to 40 m/s in 5 seconds. Calculate its acceleration.8 m/s275 m/s23 m/s25 m/s24A home-made rocket accelerates uniformly from rest at a rate of 500 m/s2 for 0.1 seconds. Calculate its launch velocity.500 m/s0.0002 m/s50 m/s5000 m/s5A racing car accelerates uniformly from rest to 40 m/s over a distance of 400 m. Calculate its acceleration.0.05 m/s20.2 m/s22 m/s28 m/s26A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s2. Calculate the distance which it covers during this time.2 m46.9 m120 m30 m
Solution
The correct unit for acceleration is Metres per second squared.
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To calculate the acceleration of the lorry, you use the formula for acceleration which is final velocity minus initial velocity divided by time. In this case, the final velocity is 20 m/s, the initial velocity is 0 (since the lorry started from rest), and the time is 10 seconds. So, (20 m/s - 0) / 10 s = 2 m/s^2. So, the acceleration of the lorry is 2 m/s^2.
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For the car, the final velocity is 40 m/s, the initial velocity is 15 m/s, and the time is 5 seconds. So, (40 m/s - 15 m/s) / 5 s = 5 m/s^2. So, the acceleration of the car is 5 m/s^2.
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For the home-made rocket, the acceleration is given as 500 m/s^2 and the time is 0.1 seconds. The launch velocity can be calculated by multiplying the acceleration by the time. So, 500 m/s^2 * 0.1 s = 50 m/s. So, the launch velocity of the rocket is 50 m/s.
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For the racing car, the final velocity is 40 m/s, the distance covered is 400 m, and it started from rest. The formula for acceleration in this case is (final velocity^2 - initial velocity^2) / (2 * distance). So, (40 m/s)^2 - 0 / (2 * 400 m) = 2 m/s^2. So, the acceleration of the racing car is 2 m/s^2.
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For the horse, the final velocity is 10 m/s, the initial velocity is 5 m/s, and the acceleration is 1.25 m/s^2. The distance covered can be calculated using the formula (final velocity^2 - initial velocity^2) / (2 * acceleration). So, (10 m/s)^2 - (5 m/s)^2 / (2 * 1.25 m/s^2) = 20 m. So, the distance covered by the horse is 20 m.
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