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Which of the following is the correct unit for acceleration?Metres squared per second squaredMetres per second squaredMetres squared per secondMetres per second2A lorry accelerates uniformly from rest to 20 m/s in 10 seconds.  Calculate its acceleration.10 m/s22 m/s20.5 m/s2200 m/s23A car accelerates uniformly from 15 to 40 m/s in 5 seconds.  Calculate its acceleration.8 m/s275 m/s23 m/s25 m/s24A home-made rocket accelerates uniformly from rest at a rate of 500 m/s2 for 0.1 seconds.  Calculate its launch velocity.500 m/s0.0002 m/s50 m/s5000 m/s5A racing car accelerates uniformly from rest to 40 m/s over a distance of 400 m.  Calculate its acceleration.0.05 m/s20.2 m/s22 m/s28 m/s26A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s2.  Calculate the distance which it covers during this time.2 m46.9 m120 m30 m

Question

Which of the following is the correct unit for acceleration?Metres squared per second squaredMetres per second squaredMetres squared per secondMetres per second2A lorry accelerates uniformly from rest to 20 m/s in 10 seconds.  Calculate its acceleration.10 m/s22 m/s20.5 m/s2200 m/s23A car accelerates uniformly from 15 to 40 m/s in 5 seconds.  Calculate its acceleration.8 m/s275 m/s23 m/s25 m/s24A home-made rocket accelerates uniformly from rest at a rate of 500 m/s2 for 0.1 seconds.  Calculate its launch velocity.500 m/s0.0002 m/s50 m/s5000 m/s5A racing car accelerates uniformly from rest to 40 m/s over a distance of 400 m.  Calculate its acceleration.0.05 m/s20.2 m/s22 m/s28 m/s26A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s2.  Calculate the distance which it covers during this time.2 m46.9 m120 m30 m

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Solution

The correct unit for acceleration is Metres per second squared.

  1. To calculate the acceleration of the lorry, you use the formula for acceleration which is final velocity minus initial velocity divided by time. In this case, the final velocity is 20 m/s, the initial velocity is 0 (since the lorry started from rest), and the time is 10 seconds. So, (20 m/s - 0) / 10 s = 2 m/s^2. So, the acceleration of the lorry is 2 m/s^2.

  2. For the car, the final velocity is 40 m/s, the initial velocity is 15 m/s, and the time is 5 seconds. So, (40 m/s - 15 m/s) / 5 s = 5 m/s^2. So, the acceleration of the car is 5 m/s^2.

  3. For the home-made rocket, the acceleration is given as 500 m/s^2 and the time is 0.1 seconds. The launch velocity can be calculated by multiplying the acceleration by the time. So, 500 m/s^2 * 0.1 s = 50 m/s. So, the launch velocity of the rocket is 50 m/s.

  4. For the racing car, the final velocity is 40 m/s, the distance covered is 400 m, and it started from rest. The formula for acceleration in this case is (final velocity^2 - initial velocity^2) / (2 * distance). So, (40 m/s)^2 - 0 / (2 * 400 m) = 2 m/s^2. So, the acceleration of the racing car is 2 m/s^2.

  5. For the horse, the final velocity is 10 m/s, the initial velocity is 5 m/s, and the acceleration is 1.25 m/s^2. The distance covered can be calculated using the formula (final velocity^2 - initial velocity^2) / (2 * acceleration). So, (10 m/s)^2 - (5 m/s)^2 / (2 * 1.25 m/s^2) = 20 m. So, the distance covered by the horse is 20 m.

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