The number of isomers for the compound with molecular formula C2BrCl Fl

To determine the number of isomers for a compound with the molecular formula C2BrCl, we need to consider the different ways in which the atoms can be arranged.

Step 1: Identify the different atoms present in the compound. In this case, we have carbon (C), bromine (Br), and chlorine (Cl).

Step 2: Determine the number of each type of atom in the compound. The molecular formula C2BrCl tells us that there are 2 carbon atoms, 1 bromine atom, and 1 chlorine atom.

Step 3: Consider the different ways in which the atoms can be arranged. In this case, we have two carbon atoms, which can be arranged in different positions. We also have one bromine atom and one chlorine atom, which can be attached to either of the carbon atoms.

Step 4: Calculate the number of possible arrangements. For the carbon atoms, there are two possible positions: carbon 1 and carbon 2. For each position, there are two possible attachments: bromine or chlorine. Therefore, we have a total of 2 positions x 2 attachments = 4 possible arrangements.

Therefore, the compound with the molecular formula C2BrCl has 4 isomers.