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How is the Hfusion used to calculate volume of liquid frozen that produces 1 kJ of energy?A.1kJ 1/Hfusion mol/g g/ml liquidB.1kJ 1/Hfusion g/mol ml/g liquidC.1kJ Hfusion mol/g g/ml liquidD.1kJ Hfusion g/mol ml/g liquid

Question

How is the Hfusion used to calculate volume of liquid frozen that produces 1 kJ of energy?A.1kJ 1/Hfusion mol/g g/ml liquidB.1kJ 1/Hfusion g/mol ml/g liquidC.1kJ Hfusion mol/g g/ml liquidD.1kJ Hfusion g/mol ml/g liquid

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Solution

The heat of fusion (Hfusion) is the amount of energy required to change a substance from the solid phase to the liquid phase at its melting point. This energy will be released when the substance changes from the liquid phase back to the solid phase.

To calculate the volume of liquid frozen that produces 1 kJ of energy, you would use the following steps:

  1. Convert the energy produced (1 kJ) to the same units as the heat of fusion (usually J/g). 1 kJ = 1000 J.

  2. Use the heat of fusion (Hfusion) to find out how many grams of the substance can be frozen with that amount of energy. This is done by dividing the energy by the heat of fusion (1kJ / Hfusion). The result will be in grams.

  3. Convert the mass of the substance to volume. This is done by multiplying the mass by the density of the substance in its liquid state (g/ml).

So, the correct answer is B. 1kJ 1/Hfusion g/mol ml/g liquid. This equation takes into account the energy produced (1kJ), the heat of fusion (1/Hfusion), the molar mass of the substance (g/mol), and the density of the substance in its liquid state (ml/g).

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