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How much energy is generated from freezing 2.5 g water?A.2.5 g 1 mol/18.02 g (285.83) kJ/molB.2.5 g 1 mol/18.02 g 40.65 kJ/molC.2.5 g 1 mol/18.02 g 4.186 kJ/molD.2.5 g 1 mol/18.02 g (6.03) kJ/molSUBMITarrow_backPREVIOUS

Question

How much energy is generated from freezing 2.5 g water?A.2.5 g 1 mol/18.02 g (285.83) kJ/molB.2.5 g 1 mol/18.02 g 40.65 kJ/molC.2.5 g 1 mol/18.02 g 4.186 kJ/molD.2.5 g 1 mol/18.02 g (6.03) kJ/molSUBMITarrow_backPREVIOUS

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Solution

The question is asking how much energy is generated from freezing 2.5 g of water. To answer this, we need to use the heat of fusion of water, which is the amount of energy needed to change 1 g of water from the liquid to the solid state without changing its temperature. The heat of fusion for water is approximately 334 J/g.

Here are the steps to solve this:

  1. Convert grams of water to moles. The molar mass of water is approximately 18.02 g/mol. So, 2.5 g of water is 2.5 g * (1 mol/18.02 g) = 0.1387 mol.

  2. Multiply the moles of water by the heat of fusion (in kJ, since the options are in kJ). The heat of fusion for water is approximately 6.01 kJ/mol. So, the energy generated is 0.1387 mol * 6.01 kJ/mol = 0.833 kJ.

So, none of the options A, B, C, or D are correct. The correct answer should be approximately 0.833 kJ.

This problem has been solved

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Question 2 of 10Constants for waterHvap 40.65 kJ/molHf -285.83 kJ/molHfusion 6.03 kJ/molspecific heat 4.186 J/gCmolar mass 18.02 gHow much energy is released when 6.0 g of water is condensed from water vapor?A.6.0 g 1 mol/18.02 g 6.03 kJ/molB.6.0 g 1 mol/18.02 g 40.65 kJ/molC.6.0 g 1 mol/18.02 g (-285.83 kJ/mol)D.6.0 g 1 mol/18.02 g 4.186 kJ/molSUBMITarrow_backPREVIOUS

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