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There are two bags containing only white and blue marbles.Bag A has 9 white marbles and 11 blue marbles.Bag B has 6 white marbles and 6 blue marbles.A marble is randomly chosen from each bag.List these events from least likely to most likely.Event 1: choosing a white or blue marble from Bag A.Event 2: choosing a white marble from Bag B.Event 3: choosing a white marble from Bag A.Event 4: choosing a red marble from Bag B.Least likely Most likelyEvent ,  Event ,  Event ,  Event

Question

There are two bags containing only white and blue marbles.Bag A has 9 white marbles and 11 blue marbles.Bag B has 6 white marbles and 6 blue marbles.A marble is randomly chosen from each bag.List these events from least likely to most likely.Event 1: choosing a white or blue marble from Bag A.Event 2: choosing a white marble from Bag B.Event 3: choosing a white marble from Bag A.Event 4: choosing a red marble from Bag B.Least likely Most likelyEvent ,  Event ,  Event ,  Event

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Solution

To answer this question, we first need to calculate the probability of each event:

Event 1: Choosing a white or blue marble from Bag A. Since Bag A only contains white and blue marbles, the probability of this event is 1 (or 100%).

Event 2: Choosing a white marble from Bag B. Bag B contains 6 white marbles out of a total of 12 marbles, so the probability of this event is 6/12 = 0.5 (or 50%).

Event 3: Choosing a white marble from Bag A. Bag A contains 9 white marbles out of a total of 20 marbles, so the probability of this event is 9/20 = 0.45 (or 45%).

Event 4: Choosing a red marble from Bag B. Since Bag B does not contain any red marbles, the probability of this event is 0.

So, the events from least likely to most likely are:

Least likely: Event 4 (choosing a red marble from Bag B) Next: Event 3 (choosing a white marble from Bag A) Next: Event 2 (choosing a white marble from Bag B) Most likely: Event 1 (choosing a white or blue marble from Bag A)

This problem has been solved

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