The hybridisation of ‘P’ in PO4–3 ion is the same as in :-I in ICl4– S in SO3  N in NO3–S in SO3–2

The hybridization of an atom in a molecule or ion is determined by the number of 'electron domains' around the atom. An electron domain is a lone pair of electrons or a bond (single, double, or triple).

In the PO4^3- ion, the phosphorus atom (P) is surrounded by four oxygen atoms, forming four single bonds. Therefore, it has four electron domains and is sp3 hybridized.

Let's compare this to the other options:

1. I in ICl4–: The iodine atom in ICl4– is surrounded by four chlorine atoms and has one lone pair of electrons, giving it five electron domains. Therefore, it is sp3d hybridized.

2. S in SO3: The sulfur atom in SO3 is surrounded by three oxygen atoms, forming one double bond and two single bonds. Therefore, it has three electron domains and is sp2 hybridized.

3. N in NO3–: The nitrogen atom in NO3– is surrounded by three oxygen atoms, forming one double bond and two single bonds. Therefore, it has three electron domains and is sp2 hybridized.

4. S in SO3^2-: The sulfur atom in SO3^2- is surrounded by three oxygen atoms, forming three single bonds. Therefore, it has three electron domains and is sp3 hybridized.

So, the hybridization of P in PO4^3- is the same as in S in SO3^2-.