Solve the equation 4, x, squared, plus, 4, x, minus, 1, equals, 04x 2 +4x−1=0 to the nearest tenth.

The given equation is a quadratic equation of the form ax^2 + bx + c = 0. The equation is 4x^2 + 4x - 1 = 0.

Step 1: Identify the coefficients a, b, and c in the equation. Here, a = 4, b = 4, and c = -1.

Step 2: Use the quadratic formula to solve for x. The quadratic formula is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Step 3: Substitute the values of a, b, and c into the formula.

x = [-4 ± sqrt((4)^2 - 44(-1))] / (2*4) x = [-4 ± sqrt(16 + 16)] / 8 x = [-4 ± sqrt(32)] / 8 x = [-4 ± 5.66] / 8

Step 4: Solve for x.

x = [-4 + 5.66] / 8 = 0.21 (to the nearest tenth) x = [-4 - 5.66] / 8 = -1.2 (to the nearest tenth)

So, the solutions to the equation 4x^2 + 4x - 1 = 0 are x = 0.2 and x = -1.2.