Solve the equation 5, x, squared, minus, 2, x, minus, 5, equals, 05x 2 −2x−5=0 to the nearest tenth.

The given equation is a quadratic equation in the form ax^2 + bx + c = 0, where a = 5, b = -2, and c = -5.

The solutions to a quadratic equation are given by the quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / (2a)

Let's plug the values of a, b, and c into the quadratic formula:

x = [2 ± sqrt((-2)^2 - 45(-5))] / (2*5) x = [2 ± sqrt(4 + 100)] / 10 x = [2 ± sqrt(104)] / 10 x = [2 ± 10.2] / 10

So, the solutions to the equation are:

x = (2 + 10.2) / 10 = 1.22 x = (2 - 10.2) / 10 = -0.82

So, the solutions to the equation 5x^2 - 2x - 5 = 0 are x = 1.2 and x = -0.8 to the nearest tenth.

The given equation is a quadratic equation in the form ax^2 + bx + c = 0, where a = 5, b = -2, and c = -5.

The solutions to a quadratic equation are given by the quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / (2a)

Let's plug the values of a, b, and c into the quadratic formula:

x = [2 ± sqrt((-2)^2 - 45(-5))] / (2*5) x = [2 ± sqrt(4 + 100)] / 10 x = [2 ± sqrt(104)] / 10 x = [2 ± 10.2] / 10

So, the solutions to the equation are:

x = (2 + 10.2) / 10 = 1.22 x = (2 - 10.2) / 10 = -0.82

So, the solutions to the equation 5x^2 - 2x - 5 = 0 are x = 1.2 and x = -0.8 to the nearest tenth.

Sure, let's solve the equation step by step.

1. The given equation is: $5x^2 - 2x - 5 = 0$

2. To solve this quadratic equation, we can use the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ where $a = 5$, $b = -2$, and $c = -5$.

3. First, calculate the discriminant ($\Delta$): $\Delta = b^2 - 4ac$ $\Delta = (-2)^2 - 4(5)(-5)$ $\Delta = 4 + 100$ $\Delta = 104$

4. Now, apply the quadratic formula: $x = \frac{-(-2) \pm \sqrt{104}}{2(5)}$ $x = \frac{2 \pm \sqrt{104}}{10}$

5. Simplify the square root of 104: $\sqrt{104} \approx 10.2$

6. Substitute back into the formula: $x = \frac{2 \pm 10.2}{10}$

7. Calculate the two possible values for $x$: $x_1 = \frac{2 + 10.2}{10} = \frac{12.2}{10} = 1.2$ $x_2 = \frac{2 - 10.2}{10} = \frac{-8.2}{10} = -0.8$

8. Therefore, the solutions to the equation $5x^2 - 2x - 5 = 0$ to the nearest tenth are: $x \approx 1.2$ $x \approx -0.8$

The given equation is a quadratic equation of the form ax^2 + bx + c = 0. The equation is 5x^2 - 2x - 5 = 0.

Step 1: Identify the coefficients a, b, and c in the equation. Here, a = 5, b = -2, and c = -5.

Step 2: Use the quadratic formula to solve for x. The quadratic formula is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Step 3: Substitute the values of a, b, and c into the formula.

x = [2 ± sqrt((-2)^2 - 45(-5))] / (2*5) x = [2 ± sqrt(4 + 100)] / 10 x = [2 ± sqrt(104)] / 10 x = [2 ± 10.2] / 10

Step 4: Solve for x.

x = (2 + 10.2) / 10 = 1.22 x = (2 - 10.2) / 10 = -0.82

So, the solutions to the equation 5x^2 - 2x - 5 = 0 are x = 1.2 and x = -0.8 to the nearest tenth.