Two point charges of -2.0 C are fixed at opposite ends of a meter stick. Where on the meterstick (if anywhere!) could (a) a free electron and (b) a free proton be placed so that they arein electrostatic equilibrium (and won’t move).

The charge to the left in the figure above has a magnitude of 5.50 nC, and charge to the right has a magnitude of 1.375 nC. The distance between them d is 6.50 m. Where can you place an electron along x other than at infinity such that it is in static equilibrium? Take the origin of coordinates at the left charge.x =:

Two free point charges +4e and +e are placed a distance a apart. Where should a third point charge q be placedbetween them such that the entire system may be in equilibrium? What should be the magnitude and sign of q?What type of equilibrium will it be?

The four point charges shown in the diagram below are situated at the corners of a square. The charges Q1 and Q3 are + 2μC; Q2 is -6 μC, and Q is a positive charge.The resultant force on Q is:Select one:a.Directed away from q2.b.Directed away from q1.c.Directed towards q2.d.Directed away from q3.e.Zero.

Two electrons each are fixed at a distance '2d'. A third charge proton placed at the midpoint is displaced slightly by a distance x (x << d) perpendicular to the line joining the two fixed charges. Proton will execute simple harmonic motion having angular frequency: (m = mass of charged particle)

A proton and an electron are placed in a uniform electric field :-The magnitude of the electric force acting on them will be equal.The electric force acting on them will be equal.The magnitude of their acceleration will be equal.Their acceleration will be equal.