Find the equation of the line that passes through the following two points:(3, -7) and (7, 2)
Question
Find the equation of the line that passes through the following two points:(3, -7) and (7, 2)
Solution 1
Step 1: Find the slope (m) of the line. The formula to find the slope between two points (x1, y1) and (x2, y2) is (y2 - y1) / (x2 - x1).
Using the given points (3, -7) and (7, 2), the slope m = (2 - (-7)) / (7 - 3) = 9 / 4 = 2.25
Step 2: Use the point-slope form of a line equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
Using the point (3, -7) and the slope 2.25, the equation becomes y - (-7) = 2.25(x - 3).
Step 3: Simplify the equation.
y + 7 = 2.25x - 6.75
Subtract 7 from both sides to get the final equation of the line:
y = 2.25x - 13.75
Solution 2
Step 1: Find the slope (m) of the line. The formula to find the slope between two points (x1, y1) and (x2, y2) is (y2 - y1) / (x2 - x1).
Using the given points (3, -7) and (7, 2), the slope m = (2 - (-7)) / (7 - 3) = 9 / 4 = 2.25
Step 2: Use the point-slope form of a line, which is y - y1 = m(x - x1). You can use either of the given points for (x1, y1). Let's use (3, -7).
Substituting the values into the equation, we get y - (-7) = 2.25(x - 3)
Step 3: Simplify the equation.
y + 7 = 2.25x - 6.75
Subtract 7 from both sides to solve for y:
y = 2.25x - 13.75
So, the equation of the line that passes through the points (3, -7) and (7, 2) is y = 2.25x - 13.75.
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