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A car comes to a skidding stop in 15m. The force on the car due to the road is 1000 N. The workdone by road on the car and car on the road respectively is(A) –15 kJ, zero (B) zero, 15 kJ(C) zero, zero (D) –15 kJ, 15 kJ

Question

A car comes to a skidding stop in 15m. The force on the car due to the road is 1000 N. The workdone by road on the car and car on the road respectively is(A) –15 kJ, zero (B) zero, 15 kJ(C) zero, zero (D) –15 kJ, 15 kJ

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Solution

To find the work done by the road on the car and the car on the road, we can use the formula:

Work = Force x Distance

Given that the force on the car due to the road is 1000 N and the car comes to a skidding stop in 15 m, we can calculate the work done by the road on the car:

Work done by road on the car = Force x Distance = 1000 N x 15 m = 15000 N·m = 15 kJ (since 1 kJ = 1000 N·m)

Therefore, the work done by the road on the car is 15 kJ.

Now, to find the work done by the car on the road, we need to consider that the car is coming to a stop. In this case, the work done by the car on the road is equal in magnitude but opposite in sign to the work done by the road on the car.

So, the work done by the car on the road is also -15 kJ.

Therefore, the correct answer is (D) –15 kJ, 15 kJ.

This problem has been solved

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