Solomon who was driving at 25m/s approaches a stoplight. The light turns yellow, and Solomon applies the brakes and skids to a stop. If Solomon's accelaration is -10m/s2, then what is the displacement of the car during skidding?a.45mb.31.25mc.35.25md.35m
Question
Solomon who was driving at 25m/s approaches a stoplight. The light turns yellow, and Solomon applies the brakes and skids to a stop. If Solomon's accelaration is -10m/s2, then what is the displacement of the car during skidding?a.45mb.31.25mc.35.25md.35m
Solution
The displacement of the car can be found using the equation of motion:
v^2 = u^2 + 2as
where: v = final velocity u = initial velocity a = acceleration s = displacement
Rearranging the equation to solve for s, we get:
s = (v^2 - u^2) / 2a
Plugging in the given values:
s = ((0 m/s)^2 - (25 m/s)^2) / (2*-10 m/s²) s = (-625 m²/s²) / -20 m/s² s = 31.25 m
Therefore, the displacement of the car during skidding is 31.25 m.
The correct answer is:
b. 31.25m
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