The new velocity of second charged particle has a magnitude `x' times the initial velocity, where x is

the magnitude of a charge on a particle which is moving with 10 metre per second is 2 coulomb now the velocity of the charge is doubled, then new charge is

A positively charged particle (charge q, mass m) is moving with constant velocity (of magnitude v0) in a region of space. In that region, a uniform electric field (of strength E) is applied for some time such that particle deviates by 60∘ and is moving twice as fast. The time for which the field acts is xmv0qE. Find the value of x2.

When the distance between two charged particles is doubled, theforce between them becomes

Velocity of particle remains constant:

The electric field and initial velocity of the charged particle are inclined at angleChoose answer: 60° 30° 90° 150°