A pulling force of 7 N to the left , a pushing force of 4 N to the right and a pulling force of 4 N to the right acts on a box that is on a frictionless surface. What is the net force acting on the box?Group of answer choices8 N to the right15 N to the right1 N to the right11 N to the left
Question
A pulling force of 7 N to the left , a pushing force of 4 N to the right and a pulling force of 4 N to the right acts on a box that is on a frictionless surface. What is the net force acting on the box?Group of answer choices8 N to the right15 N to the right1 N to the right11 N to the left
Solution
To find the net force, we need to add up all the forces acting on the box. However, we need to consider the direction of the forces as well.
- A pulling force of 7 N to the left: We can consider this as -7 N (negative because it's to the left).
- A pushing force of 4 N to the right: We can consider this as +4 N (positive because it's to the right).
- A pulling force of 4 N to the right: We can consider this as +4 N (positive because it's to the right).
Now, add all these forces together:
-7 N (left) + 4 N (right) + 4 N (right) = 1 N to the right
So, the net force acting on the box is 1 N to the right.
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