Sure, here is a simple C++ program that can solve the problem: ```cpp #include using namespace std; int main() { int N, threshold; cin >> N; int* arr = new int[N]; for(int i=0; i > arr[i]; } cin >> threshold; int count = 0; for(int i=0; i<N; i++) { if(arr[i] < threshold) { count++; } } cout << count; delete[] arr; return 0; } ``` This program works as follows: 1. It first reads the number of elements in the array (N) and the array elements from the user. 2. It then reads the threshold value from the user. 3. It initializes a counter (count) to 0. 4. It then iterates over each element in the array. If an element is less than the threshold, it increments the counter. 5. Finally, it prints the counter (which represents the number of elements less than the threshold) and deletes the dynamically allocated array to free up memory.

Meet Sandeep, a programmer working on a program to efficiently count how many values in an array fall below a user-specified threshold. Users input an array and set a threshold value. The program, utilizing pointers, swiftly determines and displays the count of elements in the array that are less than the specified threshold. You have to assist Sandeep in completing the program efficiently.Input format :The first line of input consists of an integer N, representing the number of elements in the array.The second line consists of N space-separated positive integers, representing the array elements.The third line consists of an integer, representing the threshold value.Output format :The output prints the integer representing the count of elements that are less than the specified threshold value.Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:1 ≤ N ≤ 501 ≤ array elements ≤ 100Sample test cases :Input 1 :578 65 75 82 5475Output 1 :2Input 2 :888 92 70 65 45 82 91 7780Output 2 :4

Question

Meet Sandeep, a programmer working on a program to efficiently count how many values in an array fall below a user-specified threshold. Users input an array and set a threshold value. The program, utilizing pointers, swiftly determines and displays the count of elements in the array that are less than the specified threshold. You have to assist Sandeep in completing the program efficiently.Input format :The first line of input consists of an integer N, representing the number of elements in the array.The second line consists of N space-separated positive integers, representing the array elements.The third line consists of an integer, representing the threshold value.Output format :The output prints the integer representing the count of elements that are less than the specified threshold value.Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:1 ≤ N ≤ 501 ≤ array elements ≤ 100Sample test cases :Input 1 :578 65 75 82 5475Output 1 :2Input 2 :888 92 70 65 45 82 91 7780Output 2 :4

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Solution

Sure, here is a simple C++ program that can solve the problem:

#include <iostream>
using namespace std;

int main() {
    int N, threshold;
    cin >> N;
    int* arr = new int[N];
    for(int i=0; i<N; i++) {
        cin >> arr[i];
    }
    cin >> threshold;
    int count = 0;
    for(int i=0; i<N; i++) {
        if(arr[i] < threshold) {
            count++;
        }
    }
    cout << count;
    delete[] arr;
    return 0;
}

This program works as follows:

It first reads the number of elements in the array (N) and the array elements from the user.
It then reads the threshold value from the user.
It initializes a counter (count) to 0.
It then iterates over each element in the array. If an element is less than the threshold, it increments the counter.
Finally, it prints the counter (which represents the number of elements less than the threshold) and deletes the dynamically allocated array to free up memory.

This problem has been solved

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