Solve the equation x, squared, plus, 10, x, minus, 45, equals, 0x 2 +10x−45=0 to the nearest tenth.

The given equation is a quadratic equation in the form ax^2 + bx + c = 0, where a = 1, b = 10, and c = -45.

To solve for x, we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Substituting the values of a, b, and c into the formula, we get:

x = [-10 ± sqrt((10)^2 - 41(-45))] / (2*1) x = [-10 ± sqrt(100 + 180)] / 2 x = [-10 ± sqrt(280)] / 2 x = [-10 ± 16.7] / 2

So, the solutions are:

x = (-10 + 16.7) / 2 = 3.35 x = (-10 - 16.7) / 2 = -13.35

Therefore, the solutions to the equation x^2 + 10x - 45 = 0 are x = 3.35 and x = -13.35, to the nearest tenth.