Knowee
Questions
Features
Study Tools

calculate heat capacity of a bituminous coal that has the following ultimate analysis: 81.3% c; 5.3% h; 9.8% o; 1.7% n; 1.9% s.

Question

calculate heat capacity of a bituminous coal that has the following ultimate analysis: 81.3% c; 5.3% h; 9.8% o; 1.7% n; 1.9% s.

🧐 Not the exact question you are looking for?Go ask a question

Solution 1

To calculate the heat capacity of bituminous coal, we need to know the specific heat capacities of its components. The specific heat capacities of carbon (C), hydrogen (H), oxygen (O), nitrogen (N), and sulfur (S) are approximately 0.709, 14.304, 0.918, 1.04, and 0.71 J/g°C, respectively.

The heat capacity of the coal can be calculated by multiplying the percentage of each element by its specific heat capacity and then adding all these values together.

Here's the step-by-step calculation:

  1. Calculate the heat capacity contribution from each element:

    • Carbon (C): 81.3% * 0.709 J/g°C = 57.6 J/g°C
    • Hydrogen (H): 5.3% * 14.304 J/g°C = 0.76 J/g°C
    • Oxygen (O): 9.8% * 0.918 J/g°C = 9.0 J/g°C
    • Nitrogen (N): 1.7% * 1.04 J/g°C = 0.02 J/g°C
    • Sulfur (S): 1.9% * 0.71 J/g°C = 0.01 J/g°C
  2. Add all these values together to get the total heat capacity of the coal:

    Total heat capacity = 57.6 J/g°C + 0.76 J/g°C + 9.0 J/g°C + 0.02 J/g°C + 0.01 J/g°C = 67.39 J/g°C

So, the heat capacity of the bituminous coal is approximately 67.39 J/g°C.

This problem has been solved

Solution 2

To calculate the heat capacity of bituminous coal, we need to know the specific heat capacities of its constituents. The specific heat capacities of carbon (C), hydrogen (H), oxygen (O), nitrogen (N), and sulfur (S) are approximately 0.709, 14.304, 0.918, 1.04, and 0.71 J/g°C, respectively.

The heat capacity of the coal can be calculated by multiplying the percentage of each element by its specific heat capacity and then adding these values together.

For carbon (C): 81.3% * 0.709 J/g°C = 57.6 J/g°C For hydrogen (H): 5.3% * 14.304 J/g°C = 0.76 J/g°C For oxygen (O): 9.8% * 0.918 J/g°C = 9.0 J/g°C For nitrogen (N): 1.7% * 1.04 J/g°C = 0.02 J/g°C For sulfur (S): 1.9% * 0.71 J/g°C = 0.01 J/g°C

Adding these values together gives the total heat capacity of the coal:

57.6 J/g°C + 0.76 J/g°C + 9.0 J/g°C + 0.02 J/g°C + 0.01 J/g°C = 67.39 J/g°C

So, the heat capacity of the bituminous coal is approximately 67.39 J/g°C.

This problem has been solved

Similar Questions

a-Calculate the quantity of heat necessary for this transformation? b-If this heat is provided by the combustion of coal, calculate the mass of coal used?

Specific heat capacity

Specific Heat Capacity (c)

The equation below can be used to find the specific heat capacity of a substance. Work out the specific heat capacity of a substance if it takes 5,200J of energy to heat 2kg of it from 42°C to 47°C.

For the given energy flow diagram, If the calorific value of coal is 4800 kcal/kg, the amount of coal needed annually is 7413 kg 1662 kg 3981 kg 2463 kg

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.