A particle is moving up an inclined plane. Its velocity changes from 25m/s to 10m/sin 5 seconds. What is its acceleration?

A particle moves in a circle of radius 10 cm. Its linear speed is given by v = 5t, where t is in seconds and v is in m/s. The tangential acceleration is:

To find the acceleration, we need to use the formula for acceleration which is: a = Δv / Δt where: a is acceleration, Δv is the change in velocity, and Δt is the change in time. Step 1: Find the change in velocity (Δv) The change in velocity is the final velocity minus the initial velocity. In this case, the final velocity is 10 m/s and the initial velocity is 25 m/s. So, Δv = vf - vi = 10 m/s - 25 m/s = -15 m/s The negative sign indicates that the velocity is decreasing. Step 2: Find the change in time (Δt) The change in time is given as 5 seconds. Step 3: Substitute Δv and Δt into the acceleration formula a = Δv / Δt = -15 m/s / 5 s = -3 m/s² So, the acceleration of the particle is -3 m/s². The negative sign indicates that the acceleration is directed downwards, opposite to the direction of motion. ####

A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity become 20 m/s and in tenth second it travels a distance of 10 m. Then the acceleration of the particles will be

A particle travels along the xx-axis such that its velocity is given by v, left bracket, t, right bracket, equals, t, start superscript, 1, point, 5, end superscript, sine, left bracket, 2, t, plus, 5, right bracket, .v(t)=t 1.5 sin(2t+5). What is the acceleration of the particle at time t, equals, 5, question markt=5? You may use a calculator and round your answer to the nearest thousandth.

t takes 10 s for an object to accelerate from 10 m/s to 25 m/s.What is the object's average acceleration?