To find the acceleration, we need to use the formula for acceleration which is: a = Δv / Δt where: a is acceleration, Δv is the change in velocity, and Δt is the change in time. Step 1: Find the change in velocity (Δv) The change in velocity is the final velocity minus the initial velocity. In this case, the final velocity is 10 m/s and the initial velocity is 25 m/s. So, Δv = vf - vi = 10 m/s - 25 m/s = -15 m/s The negative sign indicates that the velocity is decreasing. Step 2: Find the change in time (Δt) The change in time is given as 5 seconds. Step 3: Substitute Δv and Δt into the acceleration formula a = Δv / Δt = -15 m/s / 5 s = -3 m/s² So, the acceleration of the particle is -3 m/s². The negative sign indicates that the acceleration is directed downwards, opposite to the direction of motion. ####

Draw a graph with a maximum velocity of 10m/s and time which goes up to 20s. Then draw the line for a person who waits until t=4s. They then take 2s to accelerate to v=10m/s. They continue at this speed until t=15s. Then they decelerate and come to a stop two seconds later.Using your graph, what is the velocity at time t=5s?

can I answer it like -10km/h? because my first answer is -10km/h, I arrived at this conclusion by firstly, listing all that I knew which is, a=? vf=0 vi=100kmh t=10sec, and used the standard formula for solving acceleration.

A particle is moving up an inclined plane. Its velocity changes from 25m/s to 10m/sin 5 seconds. What is its acceleration?

If a car is traveling forward at 15 m/s, how fast will it be going in 1.2 seconds if the acceleration is -10 m/s^2?

The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.a(t) = 2t + 2,    v(0) = −15,    0 ≤ t ≤ 5(a) Find the velocity at time t.v(t) = t2+2t−15 m/s(b) Find the distance traveled during the given time interval.