What happens if you try to free a pointer twice in a row?
Question
What happens if you try to free a pointer twice in a row?
Solution
When you try to free a pointer twice in a row, it leads to a situation called double freeing. This is a common programming error that can lead to serious problems.
Here's a step-by-step explanation:
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When you allocate memory dynamically using functions like
malloc(),calloc(), ornewin C or C++, a block of memory is reserved, and the address of the first byte of this memory block is returned. This address is stored in a pointer. -
When you no longer need this dynamically allocated memory, you can use the
free()function in C ordeleteoperator in C++ to deallocate the memory, making it available for future dynamic allocations. The argument tofree()ordeleteis the pointer that was returned when the memory was allocated. -
After the memory has been freed, the pointer that was used to free the memory becomes a dangling pointer, meaning it points to a memory location that has been freed.
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If you try to free the same pointer again, you're attempting to free memory that has already been deallocated. This is known as double freeing.
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Double freeing can lead to a variety of problems. In the best-case scenario, your program will crash with a runtime error. In the worst-case scenario, it can lead to undefined behavior, which can include anything from data corruption to security vulnerabilities.
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To avoid double freeing, you should always set your pointers to
NULLafter you free them. This way, if you accidentally try to free the pointer again, it will just be a no-op becausefree(NULL)is a no-op.
Similar Questions
What happens if you try to free a pointer twice in a row?The program will crash.The program will continue to run normally.Undefined behavior.The memory will be freed twice.
In which case does a pointer become a dangling pointer?
What will be the result of the following code snippet?int main() { int *ptr1, *ptr2; ptr1 = (int *)malloc(sizeof(int)); ptr2 = (int *)malloc(sizeof(int)); *ptr1 = 42; *ptr2 = *ptr1; free(ptr1); printf("%d\n", *ptr2); free(ptr2); return 0;}
What happens if a NULL pointer is dereferenced in C?Marks : 1Negative Marks : 0Answer hereIt will point to a different variableIt will cause a runtime error or crashIt will return 0It will allocate new memory
What happens if we run the following code?12345678#include <iostream>int main() { int* ptr = new int; ptr = new int; delete ptr; return 0;}Marks : 1Negative Marks : 0Answer hereThe code will not compile due to a syntax error.The code will compile and execute without any issues.The code will compile but result in a memory leak.The code will compile but result in an allocation failure.
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