A ball tied to a string takes 8 s to complete one revolution along a horizontal circle. If on pulling the cord, theradius of circle is reduced to one fourth of previous value, then time taken by ball to complete one revolution
Question
A ball tied to a string takes 8 s to complete one revolution along a horizontal circle. If on pulling the cord, theradius of circle is reduced to one fourth of previous value, then time taken by ball to complete one revolution
Solution
The time taken by a ball to complete one revolution in circular motion is determined by the formula T = 2π√(r/g), where T is the time period, r is the radius of the circle, and g is the acceleration due to gravity.
In this case, the time taken for one revolution when the radius is reduced to one fourth can be found by substituting the new radius into the formula.
Let's denote the initial time as T1 and the initial radius as r1. So, T1 = 2π√(r1/g).
When the radius is reduced to one fourth, we'll denote the new time as T2 and the new radius as r2 (which is r1/4). So, T2 = 2π√(r2/g) = 2π√((r1/4)/g).
We can simplify this to T2 = T1/2.
So, the time taken by the ball to complete one revolution when the radius is reduced to one fourth is half the initial time. If the initial time was 8 seconds, the new time will be 8/2 = 4 seconds.
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