How many aromatic isomers are possible for trichlorobenzene (C6H3Cl3) ?A 2 B 3 C 4 D 5

To determine the number of aromatic isomers for trichlorobenzene (C6H3Cl3), we need to consider the different possible arrangements of the chlorine atoms on the benzene ring.

Step 1: Start with the structure of benzene, which consists of a ring of six carbon atoms with alternating single and double bonds.

Step 2: Replace three of the hydrogen atoms on the benzene ring with chlorine atoms. There are several possible ways to do this:

• Position 1: Replace three adjacent hydrogen atoms on the same side of the ring.
• Position 2: Replace three adjacent hydrogen atoms on alternating sides of the ring.
• Position 3: Replace three non-adjacent hydrogen atoms on the same side of the ring.
• Position 4: Replace three non-adjacent hydrogen atoms on alternating sides of the ring.

Step 3: Count the number of distinct arrangements.

• Position 1: There is only one possible arrangement for this position.
• Position 2: There are two possible arrangements for this position.
• Position 3: There is only one possible arrangement for this position.
• Position 4: There is only one possible arrangement for this position.

Step 4: Add up the number of distinct arrangements for each position.

1 + 2 + 1 + 1 = 5

Therefore, there are 5 possible aromatic isomers for trichlorobenzene (C6H3Cl3).

The correct answer is D) 5.