f the frequency of incident light falling on a photosensitive metal is doubled, thekinetic energy of the emitted photoelectron i

To answer the question, we need to understand the relationship between the frequency of incident light and the kinetic energy of the emitted photoelectron.

1. According to the photoelectric effect, when light of a certain frequency falls on a photosensitive metal, it can cause the emission of electrons.

2. The energy of a photon is directly proportional to its frequency. This means that higher frequency light carries more energy.

3. When a photon interacts with a metal surface, it transfers its energy to an electron in the metal. If the energy of the photon is sufficient, it can overcome the binding energy of the electron and cause it to be emitted as a photoelectron.

4. The kinetic energy of the emitted photoelectron is equal to the difference between the energy of the incident photon and the binding energy of the electron.

5. If the frequency of the incident light is doubled, the energy of the photons will also double.

6. As a result, the kinetic energy of the emitted photoelectron will also increase by the same factor.

In conclusion, if the frequency of incident light falling on a photosensitive metal is doubled, the kinetic energy of the emitted photoelectron will also double.