Radiations of frequency, (v) are incident on a photosensitive metal. The maximum kineticenergy of photoelectrons is E. When the frequency of the incident radiations is doubled, then whatis the maximum kinetic energy of the photoelectrons?

The maximum kinetic energy of emitted photoelectrons, from different metalsurfaces, depends upon:A. Intensity of incident light only ⃝B. Frequency of the incident light only ⃝C. Nature of metal surface ⃝D. Both frequency of incident light and nature of metal surface

When photons with a wavelength of 232 nm are incident on a metal with a work function =1.78 eV., the maximum kinetic energy (in eV to two decimal places) of photoelectrons emitted are

f the frequency of incident light falling on a photosensitive metal is doubled, thekinetic energy of the emitted photoelectron i

For the photoelectric effect, the maximum kinetic energy (Ek) of the photoelectrons is plotted against the frequency (v) of the incident photons as shown in figure. The slope of the graph gives

Given below are two statements:Statement I : Out of microwaves, infrared rays and ultraviolet rays, ultraviolet rays are the most effective for the emission of electrons from a metallic surface.Statement II : Above the threshold frequency, the maximum kinetic energy of photoelectrons is inversely proportional to the frequency of the incident light.In the light of above statements, choose the correct answer from the options given below