The milk and water in two vessels are in the ratio of 5: 4 and 3 : 4 respectively. In what ratio be the liquids of both the vessels mixed to obtain a new mixture in third vessel containing half milk and half water? A&M model 2Select one:a. 9 : 7b. 9 : 8c. 7 : 5d. 7 : 4e. 8 : 7
Question
The milk and water in two vessels are in the ratio of 5: 4 and 3 : 4 respectively. In what ratio be the liquids of both the vessels mixed to obtain a new mixture in third vessel containing half milk and half water? A&M model 2Select one:a. 9 : 7b. 9 : 8c. 7 : 5d. 7 : 4e. 8 : 7
Solution
To solve this problem, we need to find the ratio in which the mixtures from the two vessels should be combined to get a 1:1 ratio of milk to water in the third vessel.
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First, let's look at the milk to water ratio in the first vessel. It's 5:4, which means the fraction of milk in the first vessel is 5/(5+4) = 5/9.
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Similarly, the milk to water ratio in the second vessel is 3:4, which means the fraction of milk in the second vessel is 3/(3+4) = 3/7.
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We want the fraction of milk in the third vessel to be 1/2 (since we want half milk and half water).
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Let's assume that the amount of mixture taken from the first vessel is x and from the second vessel is y. We can set up the following equation based on the fractions of milk:
(5/9)x + (3/7)y = (1/2)(x + y)
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Simplifying this equation gives us 14x + 9y = 9x + 14y.
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Further simplifying gives us 5x = 5y, or x/y = 1/1.
So, the mixtures from the two vessels should be combined in a 1:1 ratio to get a new mixture in the third vessel containing half milk and half water. None of the options provided (a. 9 : 7, b. 9 : 8, c. 7 : 5, d. 7 : 4, e. 8 : 7) match this answer.
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