To solve this problem, we can use the formula for the maximum height reached by a projectile, which is given by:

h = (u^2) / (2g)

where:
- h is the maximum height,
- u is the initial velocity (speed of the ball when it was thrown), and
- g is the acceleration due to gravity.

Given in the problem, u = 4 m/s and g = 10 m/s^2.

Substituting these values into the formula, we get:

h = (4 m/s)^2 / (2 * 10 m/s^2)
= 16 m^2/s^2 / 20 m/s^2
= 0.8 m

So, the maximum height reached by the ball is 0.8 meters. Therefore, the correct answer is C) 0.80 mts.

Question

To solve this problem, we can use the formula for the maximum height reached by a projectile, which is given by:

h = (u^2) / (2g)

where:
- h is the maximum height,
- u is the initial velocity (speed of the ball when it was thrown), and
- g is the acceleration due to gravity.

Given in the problem, u = 4 m/s and g = 10 m/s^2.

Substituting these values into the formula, we get:

h = (4 m/s)^2 / (2 * 10 m/s^2)
  = 16 m^2/s^2 / 20 m/s^2
  = 0.8 m

So, the maximum height reached by the ball is 0.8 meters. Therefore, the correct answer is C) 0.80 mts.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula for the maximum height reached by a projectile, which is given by:

h = (u^2) / (2g)

where:
- h is the maximum height,
- u is the initial velocity (speed of the ball when it was thrown), and
- g is the acceleration due to gravity.

Given in the problem, u = 4 m/s and g = 10 m/s^2.

Substituting these values into the formula, we get:

h = (4 m/s)^2 / (2 * 10 m/s^2)
  = 16 m^2/s^2 / 20 m/s^2
  = 0.8 m

So, the maximum height reached by the ball is 0.8 meters. Therefore, the correct answer is C) 0.80 mts.

A ball is thrown up at a speed of 4 m/s. Find maximum height reached by the ballis ____ (take 210 /g m s )A) 8 mts B) -8 mts C) 0.80 mts D) -0.8 mts