A car of mass 1000 kg travelling at a speed of 36 Km/hris brought to rest over a distance of 20m. What is average retardation
Question
A car of mass 1000 kg travelling at a speed of 36 Km/hris brought to rest over a distance of 20m. What is average retardation
Solution
Step 1: Convert the speed from km/hr to m/s Speed = 36 km/hr = 36 * (1000/3600) m/s = 10 m/s
Step 2: Use the second equation of motion to find the retardation (deceleration) The equation is v^2 = u^2 - 2as, where: v = final velocity = 0 (since the car is brought to rest) u = initial velocity = 10 m/s s = distance = 20 m
Substituting these values into the equation, we get: 0 = (10)^2 - 2a20 0 = 100 - 40a
Step 3: Solve for a 40a = 100 a = 100 / 40 = 2.5 m/s^2
So, the average retardation (or deceleration) is 2.5 m/s^2.
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