An inductor with inductance L = 25.9 mH is connected to an AC power source having a peak value of 46.9 V and f = 965 Hz. Find the maximum current in the circuit. (You may enter your calculation using scientific notation.) A
Question
An inductor with inductance L = 25.9 mH is connected to an AC power source having a peak value of 46.9 V and f = 965 Hz. Find the maximum current in the circuit. (You may enter your calculation using scientific notation.) A
Solution
The maximum current in an AC circuit with an inductor can be found using the formula:
I_max = V_max / X_L
where:
- I_max is the maximum current,
- V_max is the peak voltage, and
- X_L is the inductive reactance.
The inductive reactance X_L can be calculated using the formula:
X_L = 2 * π * f * L
where:
- f is the frequency, and
- L is the inductance.
Let's plug in the given values:
X_L = 2 * π * 965 Hz * 25.9 * 10^-3 H = 157.08 Ω
Now, we can find the maximum current:
I_max = 46.9 V / 157.08 Ω = 0.299 A
So, the maximum current in the circuit is approximately 0.299 A.
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