The baby's movement can be represented on a coordinate plane.

1. The baby starts at the origin point (0,0).
2. He crawls 12 feet towards East, which can be represented as moving to the point (12,0).
3. Then he crawls 4 feet towards South, moving to the point (12,-4).
4. Finally, he crawls 9 feet towards West, ending up at the point (3,-4).

To find the distance from his initial position (0,0) to his final position (3,-4), we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as:

a² + b² = c²

where c represents the length of the hypotenuse, and a and b represent the lengths of the other two sides. In this case, a = 3 (the distance the baby is East or West of his starting point) and b = 4 (the distance the baby is North or South of his starting point).

So we have:

3² + 4² = c²
9 + 16 = c²
25 = c²

Taking the square root of both sides gives us c = 5.

So the baby is 5 feet away from his initial position.

Question

The baby's movement can be represented on a coordinate plane.

1. The baby starts at the origin point (0,0).
2. He crawls 12 feet towards East, which can be represented as moving to the point (12,0).
3. Then he crawls 4 feet towards South, moving to the point (12,-4).
4. Finally, he crawls 9 feet towards West, ending up at the point (3,-4).

To find the distance from his initial position (0,0) to his final position (3,-4), we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as:

a² + b² = c²

where c represents the length of the hypotenuse, and a and b represent the lengths of the other two sides. In this case, a = 3 (the distance the baby is East or West of his starting point) and b = 4 (the distance the baby is North or South of his starting point).

So we have:

3² + 4² = c²
9 + 16 = c²
25 = c²

Taking the square root of both sides gives us c = 5.

So the baby is 5 feet away from his initial position.

Knowee AI · Accepted Answer

The baby's movement can be represented on a coordinate plane.

1. The baby starts at the origin point (0,0).
2. He crawls 12 feet towards East, which can be represented as moving to the point (12,0).
3. Then he crawls 4 feet towards South, moving to the point (12,-4).
4. Finally, he crawls 9 feet towards West, ending up at the point (3,-4).

To find the distance from his initial position (0,0) to his final position (3,-4), we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. This can be written as:

a² + b² = c²

where c represents the length of the hypotenuse, and a and b represent the lengths of the other two sides. In this case, a = 3 (the distance the baby is East or West of his starting point) and b = 4 (the distance the baby is North or South of his starting point).

So we have:

3² + 4² = c²
9 + 16 = c²
25 = c²

Taking the square root of both sides gives us c = 5.

So the baby is 5 feet away from his initial position.

A baby crawls 12feet towards East and then 4feet towards South. He then crawls 9feet towards West. How far is he from his initial position? Question Description : 4 feet3 feet7 feet5 feet

Question

Solution

Similar Questions

Upgrade your grade with Knowee