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The sequence of numbers -10, -6, -2, 2 is*an AP with d = -16an AP with d = 4an AP with d = -4not an A.P.

Question

The sequence of numbers -10, -6, -2, 2 is*an AP with d = -16an AP with d = 4an AP with d = -4not an A.P.

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Solution

The sequence of numbers -10, -6, -2, 2 is an AP with d = 4.

Here's why:

An arithmetic progression (AP) is a sequence of numbers in which the difference of any two successive members is a constant. This constant difference is denoted by 'd'.

In the given sequence -10, -6, -2, 2, you can find 'd' by subtracting the second term from the first term, the third term from the second term, and so on.

So, -6 - (-10) = 4, -2 - (-6) = 4, and 2 - (-2) = 4.

Since the difference is the same between all pairs of successive numbers, the sequence is an AP, and d = 4.

This problem has been solved

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