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For a reaction with rate equation Rate = k[A][B][C]², how would the rate change if the concentration of reactant C is doubled while the concentrations of reactants A and B remain unchanged?Select one:a.The rate would be halved.b.The rate would quadruple.c.The rate would double.d.The rate would remain unchanged.

Question

For a reaction with rate equation Rate = k[A][B][C]², how would the rate change if the concentration of reactant C is doubled while the concentrations of reactants A and B remain unchanged?Select one:a.The rate would be halved.b.The rate would quadruple.c.The rate would double.d.The rate would remain unchanged.

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Solution

The rate equation is given as Rate = k[A][B][C]². This means that the rate of the reaction is directly proportional to the square of the concentration of reactant C.

If the concentration of reactant C is doubled, then the new rate would be k[A]B².

Squaring the term (2C) gives 4C². So, the new rate becomes k[A][B]4C².

Comparing this with the initial rate, we can see that the rate of the reaction has quadrupled.

So, the correct answer is b. The rate would quadruple.

This problem has been solved

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