For a reaction with rate equation Rate = k[A][B][C]², how would the rate change if the concentration of reactant C is doubled while the concentrations of reactants A and B remain unchanged?Select one:a.The rate would be halved.b.The rate would quadruple.c.The rate would double.d.The rate would remain unchanged.
Question
For a reaction with rate equation Rate = k[A][B][C]², how would the rate change if the concentration of reactant C is doubled while the concentrations of reactants A and B remain unchanged?Select one:a.The rate would be halved.b.The rate would quadruple.c.The rate would double.d.The rate would remain unchanged.
Solution
The rate equation is given as Rate = k[A][B][C]². This means that the rate of the reaction is directly proportional to the square of the concentration of reactant C.
If the concentration of reactant C is doubled, then the new rate would be k[A]B².
Squaring the term (2C) gives 4C². So, the new rate becomes k[A][B]4C².
Comparing this with the initial rate, we can see that the rate of the reaction has quadrupled.
So, the correct answer is b. The rate would quadruple.
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